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NYT Pips Answers for October 2, 2026

NYT Pips answers for October 2, 2026, a Friday: hints first, then the full solution for the easy, medium and hard boards. Take the hints in order and stop when you have enough — nothing below is revealed until you open it.

Today's set runs from a 10-square easy board to a 30-square hard one, a gap of 20 squares, with the hard board carrying 3 doubles against easy's 2 and 2 loose regions against 1. Constructed by Ian Livengood.

Sukie, Puzzle editor at EnergyPips

By Sukie · Puzzle editor

Easy — 10 squares, 5 dominoes

A 10-square board across 5 regions, with 1 exact sum to anchor it and 1 looser region to work around.

At 10 squares this is a typical easy board — the average is 9.9 — so nothing about its size explains an unusually long or short solve.

20% of its regions are loose against a norm of 40%, so this board is tighter than usual — more regions hand you a number outright, which is why it may have felt unusually tractable.

Where the information is on this board

Ordered from most constrained to least — which is the order worth working them in. No values are given away here, only how much each region can tell you.

  • < 2 (the top centre single square) — the pips in this region must add up to less than 2. 2 combinations of values would satisfy it in isolation.
  • = 5 (the middle left row of 2) — the pips in this region must add up to exactly 5. 3 combinations of values would satisfy it in isolation.
  • = (the top left column of 2) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
  • = (the middle centre 3-square block) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
  • = (the bottom centre row of 2) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
Hint 1 — where to start

Start with the < 2 region — the top centre single square — where the pips in this region must add up to less than 2. Work there first because only 2 combinations of values can fill it.

Hint 2 — what your tray forces

The tray carries 2 doubles: 1-1, 5-5. A double is the only tile that fits wholly inside an all-equal region, and there are 3 here.

Hint 3 — the opening region's values

The < 2 region resolves to 1. Which half of which domino supplies each is still yours to work out.

Full answer — easy board, October 2, 2026
How each region resolves.
RegionWhereValues
=the top left column of 26, 6
< 2the top centre single square1
= 5the middle left row of 23, 2
=the middle centre 3-square block1, 1, 1
=the bottom centre row of 25, 5

Every tile and the squares it covers

  • 1-1 → row 4 col 3 and row 5 col 3
  • 1-2 → row 4 col 2 and row 3 col 2
  • 6-3 → row 2 col 1 and row 3 col 1
  • 6-1 → row 1 col 1 and row 1 col 2
  • 5-5 → row 6 col 2 and row 6 col 3

Rows and columns are counted from the top-left of the board, starting at 1.

Medium — 14 squares, 7 dominoes

Two or more regions carry no rule at all today, which sounds generous and is not: unconstrained squares give you nothing to reason from, so the 4 sum regions have to carry the whole board.

At 14 squares this is a typical medium board — the average is 14.7 — so nothing about its size explains an unusually long or short solve.

Its tightest sum target is 0, against a median of 5 across every board published. A target that low forces blanks and low values, and is usually the fastest way in.

Where the information is on this board

Ordered from most constrained to least — which is the order worth working them in. No values are given away here, only how much each region can tell you.

  • = 0 (the middle right single square) — the pips in this region must add up to exactly 0 — and exactly one combination of values satisfies it, so it is forced.
  • = 8 (the middle centre row of 2) — the pips in this region must add up to exactly 8. 3 combinations of values would satisfy it in isolation.
  • = 5 (the middle centre row of 2) — the pips in this region must add up to exactly 5. 3 combinations of values would satisfy it in isolation.
  • > 2 (the middle left single square) — the pips in this region must add up to more than 2. 4 combinations of values would satisfy it in isolation.
  • > 1 (the bottom centre single square) — the pips in this region must add up to more than 1. 5 combinations of values would satisfy it in isolation.
  • no rule (the top centre single square) — No rule. A single free square — useful as somewhere to park a value the constrained regions cannot take.
  • = (the middle centre row of 2) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
  • = 11 (the middle centre row of 3) — the pips in this region must add up to exactly 11. 7 combinations of values would satisfy it in isolation.
  • no rule (the middle centre single square) — No rule. A single free square — useful as somewhere to park a value the constrained regions cannot take.
Hint 1 — where to start

Start with the = 0 region — the middle right single square — where the pips in this region must add up to exactly 0. Work there first because exactly one combination of values can fill it, so it is fully forced before you place anything.

Hint 2 — what your tray forces

The tray carries 2 doubles: 3-3, 2-2. A double is the only tile that fits wholly inside an all-equal region, and there is one here.

Hint 3 — the opening region's values

The = 0 region resolves to 0. Which half of which domino supplies each is still yours to work out.

Full answer — medium board, October 2, 2026
How each region resolves.
RegionWhereValues
no rulethe top centre single square3
=the middle centre row of 22, 2
= 8the middle centre row of 23, 5
> 2the middle left single square4
= 11the middle centre row of 31, 5, 5
= 0the middle right single square0
no rulethe middle centre single square1
= 5the middle centre row of 23, 2
> 1the bottom centre single square2

Every tile and the squares it covers

  • 2-1 → row 5 col 2 and row 4 col 2
  • 3-3 → row 1 col 4 and row 2 col 4
  • 5-2 → row 3 col 4 and row 4 col 4
  • 0-5 → row 3 col 5 and row 2 col 5
  • 1-4 → row 3 col 2 and row 3 col 1
  • 5-3 → row 3 col 3 and row 4 col 3
  • 2-2 → row 2 col 2 and row 2 col 3

Rows and columns are counted from the top-left of the board, starting at 1.

Hard — 30 squares, 15 dominoes

3 doubles in a 15-tile tray is a lot, and doubles are the most constrained tiles you can be dealt. Placing them first is not a preference today, it is the route through.

At 30 squares this is 14% larger than the average hard board, which runs 26.4. More squares means more placements to keep straight at once, and a mistake made early sits underneath more correct-looking work before you find it.

11% of its regions are loose against a norm of 28%, so this board is tighter than usual — more regions hand you a number outright, which is why it may have felt unusually tractable.

Its tightest sum target is 0, against a median of 4 across every board published. A target that low forces blanks and low values, and is usually the fastest way in.

Where the information is on this board

Ordered from most constrained to least — which is the order worth working them in. No values are given away here, only how much each region can tell you.

  • = 1 (the top right single square) — the pips in this region must add up to exactly 1 — and exactly one combination of values satisfies it, so it is forced.
  • = 5 (the middle left single square) — the pips in this region must add up to exactly 5 — and exactly one combination of values satisfies it, so it is forced.
  • = 3 (the middle centre single square) — the pips in this region must add up to exactly 3 — and exactly one combination of values satisfies it, so it is forced.
  • = 2 (the middle centre single square) — the pips in this region must add up to exactly 2 — and exactly one combination of values satisfies it, so it is forced.
  • = 3 (the middle centre single square) — the pips in this region must add up to exactly 3 — and exactly one combination of values satisfies it, so it is forced.
  • = 3 (the middle centre single square) — the pips in this region must add up to exactly 3 — and exactly one combination of values satisfies it, so it is forced.
  • = 4 (the middle centre single square) — the pips in this region must add up to exactly 4 — and exactly one combination of values satisfies it, so it is forced.
  • = 1 (the bottom left single square) — the pips in this region must add up to exactly 1 — and exactly one combination of values satisfies it, so it is forced.
  • > 5 (the bottom centre single square) — the pips in this region must add up to more than 5 — and exactly one combination of values satisfies it, so it is forced.
  • = 0 (the bottom centre single square) — the pips in this region must add up to exactly 0 — and exactly one combination of values satisfies it, so it is forced.
  • = 2 (the bottom right single square) — the pips in this region must add up to exactly 2 — and exactly one combination of values satisfies it, so it is forced.
  • = 9 (the middle right column of 2) — the pips in this region must add up to exactly 9. 2 combinations of values would satisfy it in isolation.
  • = 5 (the middle left row of 2) — the pips in this region must add up to exactly 5. 3 combinations of values would satisfy it in isolation.
  • = 7 (the middle left column of 2) — the pips in this region must add up to exactly 7. 3 combinations of values would satisfy it in isolation.
  • = 15 (the middle centre 3-square block) — the pips in this region must add up to exactly 15. 3 combinations of values would satisfy it in isolation.
  • < 3 (the bottom centre row of 2) — the pips in this region must add up to less than 3. 4 combinations of values would satisfy it in isolation.
  • = (the top left 4-square block) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
  • = (the top centre 4-square block) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
Hint 1 — where to start

Start with the = 1 region — the top right single square — where the pips in this region must add up to exactly 1. Work there first because exactly one combination of values can fill it, so it is fully forced before you place anything.

Hint 2 — what your tray forces

The tray carries 3 doubles: 3-3, 5-5, 2-2. A double is the only tile that fits wholly inside an all-equal region, and there are 2 here.

Hint 3 — the opening region's values

The = 1 region resolves to 1. Which half of which domino supplies each is still yours to work out.

Full answer — hard board, October 2, 2026
How each region resolves.
RegionWhereValues
=the top left 4-square block2, 2, 2, 2
=the top centre 4-square block5, 5, 5, 5
= 1the top right single square1
= 5the middle left single square5
= 9the middle right column of 26, 3
= 5the middle left row of 25, 0
= 7the middle left column of 24, 3
= 3the middle centre single square3
= 2the middle centre single square2
= 3the middle centre single square3
= 15the middle centre 3-square block6, 5, 4
= 3the middle centre single square3
= 4the middle centre single square4
= 1the bottom left single square1
< 3the bottom centre row of 21, 0
> 5the bottom centre single square6
= 0the bottom centre single square0
= 2the bottom right single square2

Every tile and the squares it covers

  • 4-6 → row 5 col 4 and row 6 col 4
  • 3-3 → row 4 col 2 and row 5 col 2
  • 2-3 → row 4 col 4 and row 4 col 5
  • 1-3 → row 6 col 1 and row 5 col 1
  • 1-0 → row 6 col 2 and row 6 col 3
  • 2-0 → row 2 col 2 and row 3 col 2
  • 1-5 → row 1 col 6 and row 1 col 5
  • 4-2 → row 5 col 6 and row 6 col 6
  • 3-6 → row 3 col 6 and row 4 col 6
  • 5-5 → row 1 col 4 and row 2 col 4
  • 5-6 → row 2 col 5 and row 2 col 6
  • 4-5 → row 4 col 1 and row 3 col 1
  • 2-5 → row 1 col 1 and row 2 col 1
  • 2-2 → row 1 col 2 and row 1 col 3
  • 5-0 → row 5 col 5 and row 6 col 5

Rows and columns are counted from the top-left of the board, starting at 1.

Questions about this day

What is the answer to NYT Pips on October 2, 2026?
The full solution for all three boards is on this page, below the hints. 3 doubles in a 15-tile tray is a lot, and doubles are the most constrained tiles you can be dealt. Placing them first is not a preference today, it is the route through.
Can I see a hint without seeing the whole answer?
Yes. Each difficulty has three hints in order — where to start, what your tray forces, then the values in the opening region — each behind its own disclosure, with the full solution last. Nothing is revealed until you open it.
Are these the official New York Times boards?
The puzzle data is the Times’ own, and this page reports and explains the solution. EnergyPips is not affiliated with The New York Times, and the boards are not reproduced here to play — to play, go to the Times. To play a free daily domino puzzle of our own, the rest of this site is that.
Why is the hard board harder than the easy one?
On October 2, 2026 the hard board runs 30 squares across 18 regions against the easy board’s 10 and 5, and carries 2 regions that give you no exact number to work from.

About these answers

EnergyPips is an independent site and is not affiliated with, endorsed by, or connected to The New York Times. This page reports and explains the solution to a published puzzle, constructed by Ian Livengood (easy), Rodolfo Kurchan (medium, hard) and edited by Ian Livengood — the board itself is not reproduced here to play. To play it, go to the official NYT Pips puzzle. To play a free daily domino puzzle of our own making, with a full archive, start here.

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