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NYT Pips Answers for October 4, 2026

NYT Pips answers for October 4, 2026, a Sunday: hints first, then the full solution for the easy, medium and hard boards. Take the hints in order and stop when you have enough — nothing below is revealed until you open it.

Today's set runs from an 8-square easy board to a 28-square hard one, a gap of 20 squares, with the hard board carrying 2 doubles against easy's 1 and 8 loose regions against 0. Constructed by Ian Livengood.

Sukie, Puzzle editor at EnergyPips

By Sukie · Puzzle editor

Easy — 8 squares, 4 dominoes

Almost every region here is an exact sum, which makes this an unusually arithmetic board: there is very little elimination to do and a great deal of adding up.

At 8 squares this is 19% smaller than the average easy board, which runs 9.9. A smaller grid is more forgiving: a bad tile is fewer undos away from being fixed.

0% of its regions are loose against a norm of 40%, so this board is tighter than usual — more regions hand you a number outright, which is why it may have felt unusually tractable.

Where the information is on this board

Ordered from most constrained to least — which is the order worth working them in. No values are given away here, only how much each region can tell you.

  • = 9 (the top right column of 2) — the pips in this region must add up to exactly 9. 2 combinations of values would satisfy it in isolation.
  • = 9 (the bottom centre row of 2) — the pips in this region must add up to exactly 9. 2 combinations of values would satisfy it in isolation.
  • = 7 (the middle left column of 2) — the pips in this region must add up to exactly 7. 3 combinations of values would satisfy it in isolation.
  • = (the top left row of 2) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
Hint 1 — where to start

Start with the = 9 region — the top right column of 2 — where the pips in this region must add up to exactly 9. Work there first because only 2 combinations of values can fill it.

Hint 2 — what your tray forces

The tray carries 1 double: 2-2. A double is the only tile that fits wholly inside an all-equal region, and there is one here.

Hint 3 — the opening region's values

The = 9 region resolves to 4, 5. Which half of which domino supplies each is still yours to work out.

Full answer — easy board, October 4, 2026
How each region resolves.
RegionWhereValues
=the top left row of 22, 2
= 9the top right column of 24, 5
= 7the middle left column of 22, 5
= 9the bottom centre row of 26, 3

Every tile and the squares it covers

  • 4-2 → row 1 col 3 and row 1 col 2
  • 2-2 → row 1 col 1 and row 2 col 1
  • 5-6 → row 3 col 1 and row 3 col 2
  • 3-5 → row 3 col 3 and row 2 col 3

Rows and columns are counted from the top-left of the board, starting at 1.

Medium — 14 squares, 7 dominoes

Two or more regions carry no rule at all today, which sounds generous and is not: unconstrained squares give you nothing to reason from, so the 3 sum regions have to carry the whole board.

At 14 squares this is a typical medium board — the average is 14.7 — so nothing about its size explains an unusually long or short solve.

56% of its regions are loose against a norm of 41%, so this board is vaguer than usual — there is less exact arithmetic to anchor on and more reasoning by elimination.

Its tightest sum target is 1, against a median of 5 across every board published. A target that low forces blanks and low values, and is usually the fastest way in.

Where the information is on this board

Ordered from most constrained to least — which is the order worth working them in. No values are given away here, only how much each region can tell you.

  • = 1 (the middle left single square) — the pips in this region must add up to exactly 1 — and exactly one combination of values satisfies it, so it is forced.
  • = 2 (the bottom centre single square) — the pips in this region must add up to exactly 2 — and exactly one combination of values satisfies it, so it is forced.
  • = 1 (the bottom right single square) — the pips in this region must add up to exactly 1 — and exactly one combination of values satisfies it, so it is forced.
  • < 3 (the top right single square) — the pips in this region must add up to less than 3. 3 combinations of values would satisfy it in isolation.
  • > 3 (the middle left single square) — the pips in this region must add up to more than 3. 3 combinations of values would satisfy it in isolation.
  • = (the middle centre 4-square block) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
  • no rule (the middle centre single square) — No rule. A single free square — useful as somewhere to park a value the constrained regions cannot take.
  • no rule (the middle right single square) — No rule. A single free square — useful as somewhere to park a value the constrained regions cannot take.
  • ≠ (the middle centre row of 3) — no two pip values in this region may be the same. 35 combinations of values would satisfy it in isolation.
Hint 1 — where to start

Start with the = 1 region — the middle left single square — where the pips in this region must add up to exactly 1. Work there first because exactly one combination of values can fill it, so it is fully forced before you place anything.

Hint 2 — what your tray forces

The tray carries 1 double: 5-5. With 1 all-different and 1 all-equal region on the board, those doubles are barred from the former and are the only tiles that fit wholly inside the latter — which usually pins two of them before you make a real decision.

Hint 3 — the opening region's values

The = 1 region resolves to 1. Which half of which domino supplies each is still yours to work out.

Full answer — medium board, October 4, 2026
How each region resolves.
RegionWhereValues
< 3the top right single square2
≠the middle centre row of 33, 5, 4
> 3the middle left single square6
=the middle centre 4-square block5, 5, 5, 5
= 1the middle left single square1
no rulethe middle centre single square3
no rulethe middle right single square3
= 2the bottom centre single square2
= 1the bottom right single square1

Every tile and the squares it covers

  • 1-3 → row 5 col 4 and row 4 col 4
  • 4-2 → row 2 col 4 and row 1 col 4
  • 6-5 → row 3 col 1 and row 3 col 2
  • 5-3 → row 2 col 3 and row 2 col 2
  • 5-1 → row 4 col 2 and row 4 col 1
  • 2-3 → row 5 col 3 and row 4 col 3
  • 5-5 → row 3 col 3 and row 3 col 4

Rows and columns are counted from the top-left of the board, starting at 1.

Hard — 28 squares, 14 dominoes

Two or more regions carry no rule at all today, which sounds generous and is not: unconstrained squares give you nothing to reason from, so the 8 sum regions have to carry the whole board.

At 28 squares this is a typical hard board — the average is 26.4 — so nothing about its size explains an unusually long or short solve.

44% of its regions are loose against a norm of 28%, so this board is vaguer than usual — there is less exact arithmetic to anchor on and more reasoning by elimination.

The tray holds 2 doubles against a typical 3.12. Doubles are the most constrained tiles you can be dealt, so you get fewer of the free constraints doubles normally provide, and have to find your footholds elsewhere.

Its tightest sum target is 0, against a median of 4 across every board published. A target that low forces blanks and low values, and is usually the fastest way in.

Where the information is on this board

Ordered from most constrained to least — which is the order worth working them in. No values are given away here, only how much each region can tell you.

  • = 2 (the middle centre single square) — the pips in this region must add up to exactly 2 — and exactly one combination of values satisfies it, so it is forced.
  • = 2 (the middle right single square) — the pips in this region must add up to exactly 2 — and exactly one combination of values satisfies it, so it is forced.
  • > 5 (the middle centre single square) — the pips in this region must add up to more than 5 — and exactly one combination of values satisfies it, so it is forced.
  • = 0 (the middle centre single square) — the pips in this region must add up to exactly 0 — and exactly one combination of values satisfies it, so it is forced.
  • = 3 (the bottom centre single square) — the pips in this region must add up to exactly 3 — and exactly one combination of values satisfies it, so it is forced.
  • = 3 (the top left row of 2) — the pips in this region must add up to exactly 3. 2 combinations of values would satisfy it in isolation.
  • < 2 (the top centre single square) — the pips in this region must add up to less than 2. 2 combinations of values would satisfy it in isolation.
  • = 3 (the top centre row of 2) — the pips in this region must add up to exactly 3. 2 combinations of values would satisfy it in isolation.
  • < 2 (the middle centre single square) — the pips in this region must add up to less than 2. 2 combinations of values would satisfy it in isolation.
  • = 3 (the bottom left row of 2) — the pips in this region must add up to exactly 3. 2 combinations of values would satisfy it in isolation.
  • = 8 (the top centre column of 2) — the pips in this region must add up to exactly 8. 3 combinations of values would satisfy it in isolation.
  • = (the middle left column of 3) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
  • = (the middle right column of 3) — every pip value in this region must be the same. 7 combinations of values would satisfy it in isolation.
  • no rule (the middle centre single square) — No rule. A single free square — useful as somewhere to park a value the constrained regions cannot take.
  • no rule (the bottom centre single square) — No rule. A single free square — useful as somewhere to park a value the constrained regions cannot take.
  • no rule (the bottom right single square) — No rule. A single free square — useful as somewhere to park a value the constrained regions cannot take.
  • ≠ (the middle centre row of 2) — no two pip values in this region may be the same. 21 combinations of values would satisfy it in isolation.
  • ≠ (the middle centre row of 2) — no two pip values in this region may be the same. 21 combinations of values would satisfy it in isolation.
Hint 1 — where to start

Start with the = 2 region — the middle centre single square — where the pips in this region must add up to exactly 2. Work there first because exactly one combination of values can fill it, so it is fully forced before you place anything.

Hint 2 — what your tray forces

The tray carries 2 doubles: 4-4, 2-2. With 2 all-different and 2 all-equal regions on the board, those doubles are barred from the former and are the only tiles that fit wholly inside the latter — which usually pins two of them before you make a real decision.

Hint 3 — the opening region's values

The = 2 region resolves to 2. Which half of which domino supplies each is still yours to work out.

Full answer — hard board, October 4, 2026
How each region resolves.
RegionWhereValues
= 3the top left row of 23, 0
= 8the top centre column of 25, 3
< 2the top centre single square1
= 3the top centre row of 20, 3
=the middle left column of 34, 4, 4
= 2the middle centre single square2
≠the middle centre row of 25, 4
= 2the middle right single square2
=the middle right column of 32, 2, 2
no rulethe middle centre single square3
< 2the middle centre single square1
> 5the middle centre single square6
≠the middle centre row of 21, 5
= 0the middle centre single square0
= 3the bottom left row of 20, 3
= 3the bottom centre single square3
no rulethe bottom centre single square5
no rulethe bottom right single square4

Every tile and the squares it covers

  • 6-3 → row 5 col 2 and row 4 col 2
  • 4-2 → row 6 col 6 and row 5 col 6
  • 5-1 → row 5 col 4 and row 4 col 4
  • 0-3 → row 6 col 1 and row 6 col 2
  • 4-5 → row 2 col 5 and row 2 col 4
  • 5-3 → row 1 col 3 and row 2 col 3
  • 2-3 → row 2 col 6 and row 1 col 6
  • 1-3 → row 5 col 3 and row 6 col 3
  • 2-0 → row 2 col 2 and row 1 col 2
  • 4-4 → row 3 col 1 and row 4 col 1
  • 3-4 → row 1 col 1 and row 2 col 1
  • 2-2 → row 3 col 6 and row 4 col 6
  • 0-5 → row 5 col 5 and row 6 col 5
  • 1-0 → row 1 col 4 and row 1 col 5

Rows and columns are counted from the top-left of the board, starting at 1.

Questions about this day

What is the answer to NYT Pips on October 4, 2026?
The full solution for all three boards is on this page, below the hints. Two or more regions carry no rule at all today, which sounds generous and is not: unconstrained squares give you nothing to reason from, so the 8 sum regions have to carry the whole board.
Can I see a hint without seeing the whole answer?
Yes. Each difficulty has three hints in order — where to start, what your tray forces, then the values in the opening region — each behind its own disclosure, with the full solution last. Nothing is revealed until you open it.
Are these the official New York Times boards?
The puzzle data is the Times’ own, and this page reports and explains the solution. EnergyPips is not affiliated with The New York Times, and the boards are not reproduced here to play — to play, go to the Times. To play a free daily domino puzzle of our own, the rest of this site is that.
Why is the hard board harder than the easy one?
On October 4, 2026 the hard board runs 28 squares across 18 regions against the easy board’s 8 and 4, and carries 8 regions that give you no exact number to work from.

About these answers

EnergyPips is an independent site and is not affiliated with, endorsed by, or connected to The New York Times. This page reports and explains the solution to a published puzzle, constructed by Ian Livengood (easy), Rodolfo Kurchan (medium, hard) and edited by Ian Livengood — the board itself is not reproduced here to play. To play it, go to the official NYT Pips puzzle. To play a free daily domino puzzle of our own making, with a full archive, start here.

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